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溴乙烷水解反应方程式

在碱性条件下水解:ch3ch2br+h2o=(naoh)ch3ch2oh+hbr

(1)溴乙烷在NaOH水溶液中水解生成乙醇和NaBr,反应为CH3CH2Br+NaOHH2O△CH3CH2OH+NaBr;故答案为:CH3CH2Br+NaOHH2O△CH3CH2OH+NaBr;(2)1-丙醇在浓硫酸作用下发生消去反应CH3CH2CH2OH浓硫酸△CH3CH=CH2↑+H2O,

1-溴丙烷水解:ch3ch2ch2br+naoh→ch3ch2ch2oh+nabr (条件:碱性、δ) 望采纳!!

BRCH2CH2BR+2NAOH=HOCH2CH2OH+2NABR C6H5ONA+HCL=C6H5OH+NACL OHCCHO+O2=HOOCCOOH

CH3CH2Br+NaOH加热→CH3CH2OH+NaBr

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